Question

What will be the volume (in litres) of oxygen liberated (at STP) when 17 grams of $H_2$$O_2$ decomposed on heating?

• A. 5.6 L
• B. 22.7L
• C. 11.35L
• D. 45.4L

Answer 1

The correct option is A

5.6 L

2 x 34 g of $H_2$$O_2$ gives 22400 ml of $O_2$

So, 17 g of $H_2$$O_2$ = $\frac{22400}{68}$X 17 ml $O_2$ =5600ml=5.6 L