Question

What will be the volume of gas at STP which is liberated at anode on electrolysis of $CuS{O}_4$ solution by a current of $5$ ampere for $2$ minutes?

• A. $0.0995$ L
• B. $0.0672$ L
• C. $0.0174$ L
• D. $0.0348$ L

Answer 1

Answer: (B)

$0.0672$ L

$i=5amp$

$t=2min=2\times 60sec$

$C{u}^{2+}n=2$

$AtomicMass=63.5g$

$m=\frac{AtomicMass}{n\times F}\times i\times t$

$\frac{m}{AtomicMass}=\frac{i\times t}{n\times F}$

$Moles=\frac{i\times t}{n\times F}$

$Moles=\frac{5\times 2\times 60}{2\times 96500}=0.003$

$1$ mole at STP $\to 22.4L$

$0.003$ mole at STP $\to 22.4\times 0.003=0.0672L$