What will be the volume of the air that will be expelled from a vessel of $300 c m^{3}$ when it is heated from $27^{o} C$ to $37^{o} C$ at the constant pressure will be :

310 c m^{3}

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290 c m^{3}

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10 c m^{3}

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37 c m^{3}

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Solution

The correct option is C $10 c m^{3}$
Let us consider the problem:

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Substitute all values in the above equation, we have
Implies that

$\frac{300}{300} = \frac{V_{2}}{310}$

$\Rightarrow V_{2} = 310 c m^{3}$

$Δ V = V_{2} - V_{1} = 10 c m$

Hence, the correct option is $C$

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Volume of the air that will be expelled from a vessel of 300 ${c m}^{3}$ when it is heated from $27^{\circ}$ C to $37^{\circ}$ C at the same pressure will be

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What will be the volume of the air that will be expelled from a vessel of 300 cm3 when it is heated from 27oC to 37oC at the constant pressure will be :

The correct option is C 10 cm3Let us consider the problem:V1T1=V2T2Substitute all values in the above equation, we haveImplies that300300=V2310⇒V2=310cm3ΔV=V2−V1=10 cmHence, the correct option is C

What will be the volume of the air that will be expelled from a vessel of $300 c m^{3}$ when it is heated from $27^{o} C$ to $37^{o} C$ at the constant pressure will be :