Question

What will be the volume of water displaced by a pure gold crown of mass $1000\text{g}$?(density of pure gold = $19.3{\text{g cm}}^{-3}$)

• A. $25.0\text{mL}$
• B. $51.8\text{mL}$
• C. $51.8\text{L}$
• D. $25.0\text{L}$

Answer 1

The correct option is B $51.8\text{mL}$

Given,

pure gold has a density of $19.3{\text{g cm}}^{-3}$

the volume of $1000\text{g}$ gold will be $\frac{1000}{19.3}=51.8{\text{cm}}^3$

$\because 1{\text{cm}}^3=1\text{mL}$

The volume of water displaced will be $51.8\text{mL}$.