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Law of Mass Action

What will be ...

Question

What will be the weight of $0.1$ mole of $C a C O_{3}$ in grams?

11 g

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12 g

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3 g

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10 g

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Solution

The correct option is D $10 g$
given that
0.1 mole of $C a C O_{3}$
Molecular weight $= 40 + 12 + 3 \times 16$
$= 100 g / m o l$
moles $= \frac{g r a m w e i g h t}{m o l e c u l a r w e i g h t}$
$0.1 = \frac{g r a m w e i g h t}{100}$
gram weight $= 10 g$

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