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Work done in Isothermal Irreversible Process

What will be ...

Question

What will be the work done when 1 mole of a gas expands isothermally from 25 L to 250 L against a constant pressure of 1 atm and a temperature of 300 K?

- 3542 J

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-5744 J

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- 2657 J

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- 4890 J

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Solution

The correct option is C -5744 J
The work done for an isothermal process is given by:

Work done $(W) = - n R T l n (\frac{V_{2}}{V_{1}}) = - 1 \times 8.314 \times 300 \times l n (\frac{250}{25})$

$∴$ Work done $(W) = - 5744 J$

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