What will be velocity of a satellite revolving around the earth at a height $h$ above surface of earth if radius of earth is $R .$

R^{2} \sqrt{\frac{g}{R + h}}

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R \frac{g}{(R + h)^{2}}

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R \sqrt{\frac{g}{R + h}}

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R \sqrt{\frac{R + h}{g}}

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Solution

The correct option is D $R \sqrt{\frac{g}{R + h}}$
Velocity of satellite revolving in an orbit of radius r, $v = \sqrt{\frac{G M}{r}}$
Also $G M = g R^{2}$
$⟹ v = \sqrt{\frac{g R^{2}}{r}}$
For $r = R + h$
$v = R \sqrt{\frac{g}{R + h}}$

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What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R.

The correct option is D R√gR+hVelocity of satellite revolving in an orbit of radius r, v=√GMrAlso GM=gR2⟹v=√gR2rFor r=R+hv=R√gR+h

What will be velocity of a satellite revolving around the earth at a height $h$ above surface of earth if radius of earth is $R .$

The correct option is D $R \sqrt{\frac{g}{R + h}}$
Velocity of satellite revolving in an orbit of radius r, $v = \sqrt{\frac{G M}{r}}$
Also $G M = g R^{2}$
$⟹ v = \sqrt{\frac{g R^{2}}{r}}$
For $r = R + h$
$v = R \sqrt{\frac{g}{R + h}}$