The correct option is D Copper will dissolve at anode
Redox Reactions at Cathode and Anode:
In this process of electrolysis, CuSO4 solution is electrolysed in the presence of Cu electrodes.
Thus, at cathode, Cu2+ will get reduced to Cu and at anode Cu will get oxidised to Cu2+.
Thus, the two half-cell reactions taking place are:
At cathode: Cu2+(aq)+2e−→Cu(s)
At anode: Cu(s)→Cu2+(aq)+2e−
Therefore, Copper will get deposited at cathode and copper will get dissolved at anode.
Hence, the correct options are (a) and (b).