What will happen if a strip of copper is kept immersed in a solution of silver nitrate (AgNO₃)?

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Solution

If a strip of copper is kept immersed in a solution of silver nitrate, the solution gradually becomes blue due to the formation of copper nitrate and a shiny greyish-white deposit of silver is formed on the copper strip.
2AgNO₃(aq) + Cu(s) $\to$ Cu(NO₃)₂(aq) + 2Ag(s)

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Q. A student was given two metal strips X and Y alongwith colourless silver nitrate solution to perform two separate displacement reactions. When the student placed metal strip X in silver nitrate solution for a considerable time, he observed that the solution turned blue and a coating of silver metal was formed on the strip. And when the student immersed metal strip Y in silver nitrate solution for an equal time, he observed that the solution turned light green with the formation of a coating of silver metal on the strip. The correct conclusion of the student about the identity of metals X and Y is :
(1) X is copper and Y is magnesium
(2) X is zinc and Y is copper
(3) X is iron and Y is copper
(4) X is copper and Y is iron

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What will happen if a strip of copper is kept immersed in a solution of silver nitrate (AgNO3)?

If a strip of copper is kept immersed in a solution of silver nitrate, the solution gradually becomes blue due to the formation of copper nitrate and a shiny greyish-white deposit of silver is formed on the copper strip. 2AgNO3(aq) + Cu(s) →Cu(NO3)2(aq) + 2Ag(s)

What will happen if a strip of copper is kept immersed in a solution of silver nitrate (AgNO₃)?

If a strip of copper is kept immersed in a solution of silver nitrate, the solution gradually becomes blue due to the formation of copper nitrate and a shiny greyish-white deposit of silver is formed on the copper strip.
2AgNO₃(aq) + Cu(s) $\to$ Cu(NO₃)₂(aq) + 2Ag(s)