What will be produced when Nitrobenzene is on reaction with $Sn / HCl$ ?

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Solution

Reduction:
The addition of Hydrogen or removal of oxygen is termed as reduction.
$Sn / HCl$ is used as reducing agent.
Reaction of Nitrobenzene with $Sn / HCl$ :
When Nitrobenzene is treated with $Sn / HCl$ , it undergoes reduction to produce Aniline.
At first, Aniline salt is formed which is then treated with $NaOH$ to give Aniline.
This is known as Nitrobenzene reduction.
$C_{6} H_{5} {NO}_{2} \to_{NaOH}^{Sn / HCl} C_{6} H_{5} {NH}_{2}$

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