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Common Ion Effect

What will the...

Question

What will the molarity of $P b^{2 +}$ ions in the solution after completion of the reactions?

8.4 \times 10^{- 10}

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1.6 \times 10^{- 10}

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2.8 \times 10^{- 10}

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6.1 \times 10^{- 10}

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Solution

The correct option is D $2.8 \times 10^{- 10}$
As we know, due to common ion $(I O_{3}^{⊝})$ left in the solution, the solubility $P b (I O_{3})_{2}$ decreases.
$[I O_{3}^{⊝}] \approx \frac{1.5}{50} = 0.03 M$
$S = \frac{K_{s p}}{(0.03)^{2}} = \frac{2.6 \times 10^{- 13} \times 10^{4}}{9}$
$= 0.28 \times 10^{- 9} = 2.8 \times 10^{- 10}$

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