What will the ratio AB:AC be if C divides the line segment AB in the ratio 5:12?
5:12
17:12
12:17
17:5
Given ACBC=512
Therefore, BCAC=125
ABAC=AC+BCAC=1+BCAC=1+125=175
So, the required ratio =17:5
What will be the ratio of corresponding sides formed in the construction of a similar triangle to ΔABC, if C divides the line segment AB in the ratio 8:17?
A point C divides a line segment AB in the ratio 5:6. The ratio of lengths AB:BC is ______.