Question

What will you substitute to make the following equation a linear equation

$\frac{1}{x}$ + $\frac{3}{y}$ = 1

• A. x as $\frac{1}{p}$ and y as $\frac{1}{q}$
• B. $\frac{1}{x}$ as p and $\frac{1}{y}$ as q
• C. Either A or B
• D. None of the above

Answer 1

The correct option is C

Either A or B

If we substitute x as $\frac{1}{p}$ and y as $\frac{1}{q}$ then we will get the equation as

$p+3q=1$

Now we see that the above equation is a linear equation.

If we substitute $\frac{1}{x}$ as p and $\frac{1}{y}$ as q, we will get the equation as

$p+3q=1$

It is linear equation.

So we can reduce the equation in linear form by substituting both option A and B.