What would be empirical formula mass of $C_{6} H_{6}$ ?

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Solution

Part one: Introduction of Empirical formula and the Empirical formula mass
The simplest ratio of atoms in compound is empirical formula of the compound.
Many compounds can have same empirical formula.
Empirical formula is not same to the molecular formula of the compound.
The mass of the empirical formula will be empirical formula mass.
Part two: Empirical formula mass of Benzene $(C_{6} H_{6})$
The Empirical formula of Benzene $(C_{6} H_{6})$ will be $C H$ .
The empirical formula mass of Benzene $(C_{6} H_{6})$ will be sum of Carbon $(C)$ formula mass and Hydrogen $(H)$ formula mass.
The formula mass units is Atomic mass units $(a m u)$ .
Empirical formula mass of Benzene $(C_{6} H_{6})$ is given by ,
$\begin{array}{rcl} (E m p i r i c a l f o r m u l a m a s s o f B e n z e n e (C_{6} H_{6})) & = & (F o r m u l a m a s s o f C a r b o n (C) + F o r m u l a m a s s o f H y d o r g e n (H)) \\ (E m p i r i c a l f o r m u l a m a s s o f B e n z e n e (C_{6} H_{6})) & = & 12 a m u + 1 a m u \\ (E m p i r i c a l f o r m u l a m a s s o f B e n z e n e (C_{6} H_{6})) & = & 13 a m u \end{array}$
Therefore, Empirical formula mass of Benzene $(C_{6} H_{6})$ is $13$ $a m u$ .

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