Question

What would be the approximate weight of $1.204\times {10}^{24}$ bromine atoms?

• A. 80 grams
• B. 120 grams
• C. 160 grams
• D. 180 grams
• E. 200 grams

Answer 1

The correct option is C 160 grams

The atomic weight of bromine is 80.

So, 80-gram bromine contains Na atoms.

So, $1.204\times {10}^{24}$ bromine atoms will weigh: $80÷6.02\times {10}^{23}\times 1.204\times {10}^{24}=160gram$