Question

What would be the area of right isosceles triangle of side length 'a'?

• A. $\frac{a^2}{4}$
• B. $2a^2$
• C. $a^2$
• D. $\frac{a^2}{2}$

Answer 1

The correct option is D

$\frac{a^2}{2}$

The area of the right triangle =$\frac{1}{2}\times base\times height$

Since the triangle is isosceles, base = height = a.
Therefore, the area of the right isosceles triangle = $\frac{1}{2}\times a\times a$

= $\frac{a^2}{2}$

The area of the right isosceles triangle is $\frac{a^2}{2}$