What would be the coefficient of hydrochloric acid in the following equation, after balancing the reaction?
$. . . {C l}_{2} + . . . H_{2} O \to . . . H C l + . . . H C l O_{3}$

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Solution

The correct option is C 5
Balanced chemical equation of this reaction is as follows:
$3 C l_{2} + 3 H_{2} O \to 5 H C l + H C l O_{3}$
Here, stoichiometry coefficient of $H C l$ is 5.

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{C l}_{2} +

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H C l +

H C l O_{3}

. . . K_{2} C r_{2} O_{7} + . . . H C l \to . . . K C l + . . . C r C l_{3} + . . . H_{2} O + . . . C l_{2}

. . . K_{2} {C r}_{2} O_{7} + . . . H C l \to . . . K C l + . . . C r {C l}_{3} + . . . H_{2} O + . . . {C l}_{2}

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