Question

What would be the compound formula of Strontium Bromide?

Answer 1

Strontium has two valence electrons and commonly forms $S{r}^{2+}$ ion. Bromine is a non-metal with seven valence electrons, and commonly forms the $B{r}^{-}$ion.

When strontium and bromine react with each other, we conceive of a redox process.

$Sr\left(s\right)+B{r}_2\left(l\right)\to SrB{r}_2\left(s\right)$

So, the compound formula of Strontium Bromide is $SrB{r}_2.$