The digit at the tens place of a two digit number is three times the digit at the units’ place. If the sum of this number and the number formed by reversing its digits is 88, find the number.

Q. The digit at the tens place of a two digit number is three times the digit at the units place. If the sum of this number and the number formed by reversing its digits is

88

, find the number.

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What would be the difference between the place values of the digits at the tens and units places of a number formed by the addition of the greatest six-digit number and the smallest three-digit number?

The correct option is A 81The greatest 6 digit number is =999999.The smallest 3 digit number is=100.Therefore there sum=1000099.The tens place value=90 and units place vaue =9.Therefore the difference is 81 .

The correct option is A $81$
The greatest 6 digit number is $= 999999$ .
The smallest 3 digit number is $= 100$ .
Therefore there sum $= 1000099$ .
The tens place value= $90$ and units place vaue $= 9$ .
Therefore the difference is $81$ .