Question

What would be the force of repulsion between two people with the said charge $4C$ when they are 100 m apart?

• A. $1.44\times {10}^{5}C$
• B. $14.4\times {10}^{5}C$
• C. $1.44\times {10}^{6}C$
• D. $1.44\times {10}^{7}C$

Answer 1

The correct option is D $1.44\times {10}^{7}C$

Two people have said charge $q_1=q_2=4C$.
Distance between the two people is $r=100m$
The repulsion force between the two people is $F=\frac{1}{4\pi {ϵ}_0}.\frac{q_1{q}_2}{r^2}=9\times {10}^9\times \frac{4\times 4}{(100{)}^2}=144\times {10}^5=1.44\times {10}^{7}N$