Question

What would be the output of the circuit whose boolean expression $Y=A\overline{B}+AB$ when A=1, B=0 ?

• A. 1
• B. 0
• C. Both (A) & (B)
• D. None of these

Answer 1

Answer: (A)

1

Here,

$Y=A.\overline{B}+A.B$

$Y=A(B+\overline{B})$

We know,

$B+\overline{B}=1$

$Y=A.1=A$

When $A=1,B=0$

$Y=A=1$

Option $\text{A}$ is the correct answer