What would be the value of stoichiometric coefficients of Mg and VO3−4 respectively, in the balanced net ionic equation for the given redox reaction in acidic medium: Mg(s)+VO3−4(aq)→Mg2+(aq)+V2+(aq)
A
3,2
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B
8, 16
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C
1, 1
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D
5,10
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Solution
The correct option is A 3,2
0Mg(s)++5VO3−4(aq)→+2Mg2+(aq)++2V2+(aq)
Oxidation:
0Mg(s)→+2Mg2+(aq) nf=(|2−0|)×1=2
Reduction: +5VO3−4(aq)→+2V2+(aq) nf=(|2−5|×1=3
VO3−4 is oxidising agent Mg is reducing agent.
Cross mutiply the oxidising and reducing agents with ratio of n-factors. 3Mg(s)+2VO3−4(aq)→Mg2+(aq)+V2+(aq)
Balancing all species except O and H 3Mg(s)+2VO3−4(aq)→3Mg2+(aq)+2V2+(aq)
Balance oxygen atoms by adding H2O. 3Mg(s)+2VO3−4(aq)→3Mg2+(aq)+2V2+(aq)+8H2O(l)
balance charge charge in reactant side = -6+16=+10 charge in product side = +10 so the balanced equation is 3Mg(s)+2VO3−4(aq)+16H+(aq)→3Mg2+(aq)+2V2+(aq)+8H2O(l) The coefficients of Mg and VO3−4 respectively are 3 and 2.