What would happen to Vmax, in the presence of a non-competitive inhibitor?
A
It decreases
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B
It increases
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C
Remains the same
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D
First increase then decrease
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Solution
The correct option is A It decreases In non-competitive inhibition, the inhibitor molecules do not compete with the substrates for active sites on the enzyme surface, but some other site on the enzyme. This results in a decrease in the enzyme molecules that can catalyse the reaction. Hence, Vmax is lowered. As a result, the non-competitive inhibitors cannot be completely overcome by the addition of more substrate. This leads to a decrease in Vmax of the reaction.