When $0.002$ mol of acid is added to $250$ mL of a buffer solution, $p H$ decreaes by $0.02$ units.
The buffer capacity of the system is:

0.1

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0.2

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0.3

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0.4

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Solution

The correct option is D $0.4$
Buffer capacity $= \frac{Number of moles of acid or base added to a 1L buffer}{change in pH}$

$= \frac{0.002 \times 4}{0.02} = 0.4$

Hence, the correct option is $D$

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When 0.002 mol of acid is added to 250 mL of a buffer solution, pH decreaes by 0.02 units. The buffer capacity of the system is:

The correct option is D 0.4Buffer capacity =Number of moles of acid or base added to a 1L bufferchange in pH=0.002×40.02=0.4Hence, the correct option is D

When $0.002$ mol of acid is added to $250$ mL of a buffer solution, $p H$ decreaes by $0.02$ units.
The buffer capacity of the system is:

The correct option is D $0.4$
Buffer capacity $= \frac{Number of moles of acid or base added to a 1L buffer}{change in pH}$

$= \frac{0.002 \times 4}{0.02} = 0.4$

Hence, the correct option is $D$