Question

When $0.02$ moles of $NaOH$ are added to a litre of buffer solution, its $pH$ changes from $5.75$ to $5.80$. What is its buffer capacity?

• A. $0.4$
• B. $0.05$
• C. $-0.05$
• D. $2.5$

Answer 1

Answer: (A)

$0.4$

$Buffercapacity=\frac{\frac{No.ofeqadded}{litres}}{ChangeofpH}=\frac{0.02}{0.05}=0.4$