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Question

When 0.031 of a mixture of hydrogen and oxygen was exploded, 0.003 1 of oxygen remained. The initial mixture contains (by volume)

A
60%O2
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B
40%O2
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C
50%O2
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D
30%O2
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Solution

The correct option is B 40%O2
2H2+O22H2O
x0.031x
24 ml of H2 reacts with 021 ml O2
x ml reacts with mlO2
(0.031x)x2=0.0031
0.031xx2=0.0031
0.0622xx2=(0.0031)×2
3x+0.0620.0062
3x=0.0620.0062
x=0.0186 ml
Volume of O2=0.0310.0186
+0.0124 ml.
Volume of O2=0.0310.0186
=0.0124 ml
% initial vol of O2=0.01240.031×100
=40% 0
Option b

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