231

You visited us 231 times! Enjoying our articles? Unlock Full Access!

When 0.1 mole...

Question

When 0.1 mole of $M n O_{4}^{2 -}$ is oxidized the quantity of electricity required to completely oxidise $M n O_{4}^{2 -}$ to $M n O_{4}^{-}$ is

9650 C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

96500 C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

96.50 C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 \times 96500 C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $9650 C$
$+ 7 M n O_{4}^{2 -} 1 F - \to + 6 M n O_{4}^{2 -}$
1 mole
$∴$ For 0.1 mole 0.1F is required

Suggest Corrections

Similar questions

M n O_{4}^{2 -}

M n O_{4}^{2 -}

M n O_{4}^{-}

M n O_{4}^{2 -}

M n O_{4}^{2 -}

M n O_{4}^{-}

0.1

M n O_{4}^{2 -}

M n O_{4}^{2 -}

M n O_{4}^{-}

0.1 m o l M n O_{4}^{2 -}

M n O_{4}^{2 -}

M n O_{4}^{-}

M n O_{4}^{2 -}

M n O_{4}^{2 -}

M n O_{4}^{-}

Join BYJU'S Learning Program