When 10 amine reacts with CHCl3 in ethanolic KOH, the product formed is:
A
an isocyanide
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B
an aldehyde
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C
a cyanide
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D
an alcohol
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Solution
The correct option is D an isocyanide When 10 amine reacts with CHCl3 in ethanolic KOH, an isocyanide is formed as a product. The reaction is as follows:
C6H5NH2+CHCl3+3KOH→C6H5NC+3KCl+3H2O
This reaction is also called as a carbylamine reaction.