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Question

When 10 amine reacts with CHCl3 in ethanolic KOH, the product formed is:

A
an isocyanide
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B
an aldehyde
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C
a cyanide
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D
an alcohol
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Solution

The correct option is D an isocyanide
When 10 amine reacts with CHCl3 in ethanolic KOH, an isocyanide is formed as a product.
The reaction is as follows:

C6H5NH2+CHCl3+3KOHC6H5NC+3KCl+3H2O

This reaction is also called as a carbylamine reaction.

Option A is correct.

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