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Specific Heat Capacity

When 1.25g ...

Question

When $1.25 g$ of a sample of chalk is strongly heated, $0.44 g$ ${C O}_{2}$ gas in produce. Determine the percentage of pure $C a {C O}_{3}$ in the chalk sample.

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Solution

$0.44 g C O_{2} \times \frac{1 m o l e C O_{2}}{44 g C O_{2}} \times \frac{1 m o l e C a C O_{3}}{1 m o l e C O_{2}} \times \frac{100 g C a C O_{3}}{1 m o l e C a C O_{3}} = 1 g C a C O_{3}$

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