When 1 mole H2Og and 1 mole COg are heated at 1000-C in a closed vessel of 5 litre- it will found that 40

#160; #160; #160; #160; #160; #160; #160; H _ 2 O( g ) +CO( g ) ⇌ H _ 2 ( g ) + CO _ 2 ( g ) at t=0 #160; 1mole #160; #16 ...

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Characteristics of Equilibrium Constant

When 1 mole...

Question

When $1$ mole $H_{2} O (g)$ and $1$ mole $C O (g)$ are heated at $1000^{\circ} C$ in a closed vessel of $5$ litre, it will found that $40$ % of $H_{2} O$ react at equilibrium according to $H_{2} O (g) + C O (g) ⇌ H_{2} (g) + C O_{2} (g)$ .

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1 m o l e H_{2} O_{(g)}

1 m o l e C O_{(g)}

1000^{\circ} C

5 l i t r e

40 %

H_{2} O

H_{2} O_{(g)} + C O_{(g)} ⇌ H_{2 (g)} + C O_{2 (g)}

K_{C}

1

H_{2} O

1

C O

10

1259 K

40 % H_{2} O

C O

H_{2} O (g) + C O (g) ⇌ H_{2} (g) + C O_{2} (g)

O n e m o l e

H_{2} O

o n e m o l e

C O

10 L

1260 K

40

H_{2} O (g) + C O (g) ⇌ H_{2} (g) + C O_{2} (g)

One mole of H₂O and one mole of CO are taken in 10 L vessel and heated to

725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,

Calculate the equilibrium constant for the reaction.

H_{2} O

H_{2} O (g) + C O (g) ⇌ H_{2} (g) + C O_{2} (g)

(K_{c})

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