Question

When 1 mole of A(g) is introduced in a closed rigid 1 litre vessel maintained at constant temperature the following equilibria are established A(g)⇌B(g)+C(g):KC1 C(g)⇌D(g)+B(g):KC2 The pressure at equilibrium is twice the initial pressure. Calculate the value of KC2KC1 if [C]eq[B]eq=15.

Solution

AP0−x⇌Bx+y+Cx−y Cx−y⇌Dy+By+x Given   x−yx+y=15 & 2P0=P0−x+x+y+x−y+y So  x+y=P0 x+y=P0,x−yx+y=15 ⇒x−y=P05 x=3P05,y=2P05 Kc2Kc1=(y+x)(y)(x−y)×(P0−x)(x+y)(x−y) ⇒y(P0−x)(x−y)2=y(P0−x)(P05)2 ⇒(2P05)(2P05)(P05)2=4

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