When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume becomes 60 L. Calculate entropy change for the process (Cp,m=30.96Jmole−1K−1)
A
80.2J.k−1mol−1
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B
62.42kJ.k−1mol−1
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C
120×102Jk−1mol−1
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D
27.22J.k−1mol−1
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Solution
The correct option is D27.22J.k−1mol−1 P1V1T1=P2V2T2 T2T1=63 ΔS=2.303×n{Cplog10T2T1+Rlog10P1P2} ΔS=2.303×1{30.96log1063+Rlog102010} ΔS=27.22J.k−1mol−1