When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with $A g N O_{3}$ , $x$ moles of $A g C l$ are obtained. The formula of the compound is $[C r (H_{2} O)_{6}] C l_{3}$ , $y$ is the oxidation number of $C r$ and $z$ is the coordination number of the compound. The value of $2 x + y - z$ is ___.

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Solution

The formula of the compound is $[C r (H_{2} O)_{6}] C l_{3}$ has three 3 free $C l^{-}$ ions. Since $x$ moles of $A g C l$ are obtained, the value of $x$ is 3.

The oxidation number $y$ of the central atom in $[C r (H_{2} O)_{6}]^{3 +}$ = 3. Since there are 6 ligands in the inner sphere of the complex, it is octahedral. So $z$ = 6

So, $2 \times 3 + 3 - 6 = 3$

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Similar questions

When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3},$ 3 moles of AgCl are obtained. The formula of the complex is
(a) $[C r C l_{3} (H_{2} O)_{3}] 3 H_{2} O$
(b) $[C r C l_{3} (H_{2} O)_{4}] C l_{2} .2 H_{2} O$
(c) $[C r C l_{3} (H_{2} O)_{5}] C l_{2} . H_{2} O$
(d) $[C r (H_{2} O)_{6}] C l_{3}$