When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 2 mol of AgCl are obtained. The formula of the complex is

[C r C l_{3} (H_{2} O)_{3}] .3 H_{2} O

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[C r C l_{2} (H_{2} O)_{4}] C l .2 H_{2} O

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[C r C l (H_{2} O)_{5}] C l_{2} . H_{2} O

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[C r (H_{2} O)_{6}] C l_{3}

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Solution

The correct option is C $[C r C l (H_{2} O)_{5}] C l_{2} . H_{2} O$
2 mole of $A g C l$ means $2 C l^{-}$ are given in the solution hence, the formula of the complex will be $[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O$ .

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Similar questions

When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3},$ 3 moles of AgCl are obtained. The formula of the complex is
(a) $[C r C l_{3} (H_{2} O)_{3}] 3 H_{2} O$
(b) $[C r C l_{3} (H_{2} O)_{4}] C l_{2} .2 H_{2} O$
(c) $[C r C l_{3} (H_{2} O)_{5}] C l_{2} . H_{2} O$
(d) $[C r (H_{2} O)_{6}] C l_{3}$

When 0.2 mol $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 0.4 mol of AgCl are obtained. The formula of the complex is

Q. When 1 mole of

C r C l_{3} .6 H_{2} O

is treated with excess of

A g N O_{3}

, 2 mol of AgCl are obtained. The formula of the complex is

Q. Which isomer of

C r C l_{3} .6 H_{2} O

is dark green in colour and forms one mole of AgCl with excess of

A g N O_{3}

solution -

Q. A six-coordinate complex of formula

C r C l_{6} .6 H_{2}

O is green in colour. A

0.1 M

solution of the complex when treated with excess of

A g N O_{3}

gave

28.7 g

of white precipitate. The formula of the complex would be:

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When 1 mole of CrCl3.6H2O is treated with excess of AgNO3, 2 mol of AgCl are obtained. The formula of the complex is

The correct option is C [CrCl(H2O)5]Cl2.H2O2 mole of AgCl means 2Cl− are given in the solution hence, the formula of the complex will be [Cr(H2O)5Cl]Cl2.H2O.

When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 2 mol of AgCl are obtained. The formula of the complex is

The correct option is C $[C r C l (H_{2} O)_{5}] C l_{2} . H_{2} O$
2 mole of $A g C l$ means $2 C l^{-}$ are given in the solution hence, the formula of the complex will be $[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O$ .