When $1$ % of $C_{2} H_{5} O H$ is added to $C H C l_{3}$ , the phosgene present in chloroform is converted to:

C H_{3} C O O C_{2} H_{5}

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C H_{3} C O C H_{3}

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(C H_{3} C H_{2} O)_{2} C O

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C H_{3} C O O H

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Solution

The correct option is C $(C H_{3} C H_{2} O)_{2} C O$
Phosgene reacts with ethyl alcohol to form ethyl carbonate.

$2 C_{2} H_{5} O H + C O C l_{2} \to (C_{2} H_{5} O)_{2} C O + 2 H C l$

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Similar questions

C H_{3} C O O H + C_{2} H_{5} O H ⇋ C H_{3} C O O C_{2} H_{5} + H_{2} O

C H_{3} C O O C_{2} H_{5} + H_{2} O^{+} C H_{3} C O O H + C_{2} H_{5} O H

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

= K [C H_{3} C O O C_{2} H_{5}] [N a O H]

C H C l_{3}

C H C l_{3} + \frac{1}{2} O_{2} ⟶ C O C l_{2} + H C l

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