When $10^{19}$ electrons are removed from a neutral metal plate, the electric charge on it is

-16 C

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+16 C

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10' C

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10' C

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Solution

The correct option is B +16 C
By using $Q = n e \Rightarrow Q = 10^{19} \times 1.6 \times 10^{- 19} =_{1} .6 C$ .

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