When 10^19electron are removed from a neutral metal plate, what is the electric charge

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Solution

$D e a r s t u d e n t, c h a r g e o n o n e e l e c t r o n = 1.6 \times 10^{- 19} C T o t a l c h a r g e o n 10^{19} e l e c t r o n s = 1.6 \times 10^{- 19} \times 10^{19} = 1.6 C T h e e l e c t r i c c h a r g e a c q u i r e d b y t h e p l a t e a f t e r r e m o v a l o f 10^{19} e l e c t r o n s = + 1.6 C R e g a r d s$

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