When 10-6 g of a nonvolatile substance is dissolved in 740 g of ether- its boiling point is raised 0-284- C- What is the molecular weight of the substance- Molal boiling point constant for ether is 2-11-C-kg-mol-

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Elevation in Boiling Point

When 10.6 g o...

Question

When 10.6 g of a nonvolatile substance is dissolved in 740 g of ether, its boiling point is raised ${0.284}^{\circ} C$ . What is the molecular weight of the substance? Molal boiling point constant for ether is ${2.11}^{\circ} C . k g / m o l .$

106

g/mol

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96

g/mol

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53

g/mol

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43

g/mol

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Solution

The correct option is D $106$ g/mol
The molecular weight of the solute is given by the expression
$M_{2} = \frac{K_{b} W_{2}}{Δ T_{b} W_{1}}$ where

$M_{2}$ is the molecular weight of solute, $K_{b}$ is the molal boiling point constant of the solvent,
$W_{2}$ is mass of solute, $W_{1}$ is mass of solvent and $Δ T_{b}$ is the elevation in the boiling point.

Substitute values in the above expression.
$M_{2} = \frac{2.11 \times 10.6}{0.284 \times 740} = 0.106 k g / m o l = 106 g / m o l$

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When 10.6 g of a nonvolatile substance is dissolved in 740 g of ether, its boiling point is raised 0.284∘C. What is the molecular weight of the substance? Molal boiling point constant for ether is 2.11∘C.kg/mol.

When 10.6 g of a nonvolatile substance is dissolved in 740 g of ether, its boiling point is raised ${0.284}^{\circ} C$ . What is the molecular weight of the substance? Molal boiling point constant for ether is ${2.11}^{\circ} C . k g / m o l .$