Question

When 10 g of 90% pure limestone is heated, the volume of $C{O}_2\left(inlitre\right)$ liberated at STP is:

• A. 22.4 litre
• B. 2.24 litre
• C. 20. 16 litre
• D. 2.016 litre

Answer 1

The correct option is D 2.016 litre

Mass of $CaC{O}_3$ in the sample $=10\times 90100=9g$

$\underset{100g}{\underset{1mol}{CaC{O}_3\left(s\right)}}\to CaO\left(s\right)+\underset{22.4L}{\underset{1mol}{C{O}_2\left(g\right)}}$

$9gmCaC{O}_3$ will give $(\frac{22.4}{100}\times 9)$ litre of $C{O}_2$,

$i.e.,2.016$ litre of $C{O}_2$ is librated at standard temperature and pressure in given conditions.