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Question

When 10 mL of 0.1 M acetic acid (pKa=5.0) is titrated against 10 mL of 0.1 M ammonia solution (pKb=5.0) the equivalence point occurs at pH of:

A
5
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B
6
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C
7
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D
9
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Solution

The correct option is C 7
Given, VCH3COOH=VNH3=10 mL, pKa=5.0, pKB=5.0

10 mL of 0.1 M CH3COOH will completely react with 10 mL of 0.1 M ammonia solution to give CH3COONH4 (a salt of a weak acid and a weak base).
The pH of the resulting solution can be calculated as follows:
pH=12[pKa+pKwpKb]
pH=12[5.0+145.0] pKw=14 at 25oC
pH=12×14=7

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