When $100$ g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, $n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}$ is :

\frac{n}{2}

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100

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\frac{100}{n}

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100 n

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Solution

The correct option is A $100$ g
When $100$ g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, $n C H_{2} = C H_{2} \to (C H_{2} - C H_{2}) n$ is $100$ g, because entire mass of ethylene is converted to polyethylene as there is no addition, elimination or condensation of simple molecules.

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n C H_{2} = C H_{2} ⟶ - (C H_{2} - C H_{2})_{n} -

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n C H_{2} = C H_{2} \to - (C H_{2} - C H_{2})_{n} -

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