When 100 ml of a O2−O3 mixture was passed through turpentine, there was the reduction of volume by 20 ml. If 100ml of such a mixture is heated, what will be the increase in volume?
A
10ml
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B
20ml
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C
30ml
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D
25ml
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Solution
The correct option is C10ml Ozone is highly soluble in turpentine. Thus, the decrease in volume of 20 ml is due to the solubility of ozone. Thus 100ml of a mixture contains 20 ml of ozone.
On heating, 20 ml of ozone decomposes to form 30 ml of oxygen. The net increase in volume will be (30−20)=10ml.