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Question

When 100 ml of a O2O3 mixture was passed through turpentine, there was the reduction of volume by 20 ml. If 100ml of such a mixture is heated, what will be the increase in volume?

A
10 ml
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B
20 ml
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C
30 ml
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D
25 ml
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Solution

The correct option is C 10 ml
Ozone is highly soluble in turpentine. Thus, the decrease in volume of 20 ml is due to the solubility of ozone. Thus 100ml of a mixture contains 20 ml of ozone.
On heating, 20 ml of ozone decomposes to form 30 ml of oxygen. The net increase in volume will be (3020)=10ml.
2O33O2

So, the correct option is A

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