Question

When 100 ml of a $O_2-O_3$ mixture was passed through turpentine, there was reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in volume?

Answer 1

1000 ml of mixture,

20 ml reduction in volume is 20 ml $O_3$

100 ml of mixture contains 20 ml $O_3$ and 80 ml $O_2$

When heated 20 ml $O_3$ gives 30 ml $O_2$

Then the volume becomes 110 ml

So the increase is 10 ml

Therefore the % increase in volume is 10%