Question

When 100 ml of $O_2$ and $O_3$ mixture was passed through turpentine, there was a reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in volume?

Answer 1

Volume of $O_2=xmL$

Since $O_3$ is absorbed by turpentine oil.

Volume of $O_3=(100-x)=20\Rightarrow x=80mL$

If the mixture is heated, $O_3$ will be decomposed

$O_3\stackrel{\Delta }{\to }\frac{3}{2}{O}_2$

$20mL\to \frac{3}{2}\times 20ml=30mL$

$\therefore$ Total volume now $=80ml+30mL=110mL$

$\therefore$ Increase in volume $=10mL$