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Question

When 100 ml of O2O3 mixture was passed through turpentine oil, there was reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in the volume (ml)? (Write the answer in the form of volume/2)

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Solution

O3 is absorbed in turpentine oil. Volume of O3=20 ml, and volume of O2=(10020)=80 ml. On heating O3 is converted to O2.
2O33O2
2mol 3 mol
2ml 3ml
20ml 30ml
From 20 ml of ozone, 30 ml of oxygen is formed. Hence, increase in volume =3020=10 ml.

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