When 100 ml of O2−O3 mixture was passed through turpentine oil, there was reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in the volume (ml)? (Write the answer in the form of volume/2)
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Solution
O3 is absorbed in turpentine oil. Volume of O3=20 ml, and volume of O2=(100−20)=80 ml. On heating O3 is converted to O2. 2O3⇌3O2 2mol 3 mol 2ml 3ml 20ml 30ml
From 20 ml of ozone, 30 ml of oxygen is formed. Hence, increase in volume =30−20=10 ml.