When 100V dc is applied across a coil, a current of 1A flows through it and when 100V ac of 50Hz is applied to the same coil, only 0.5A flows. The inductance of coil is
A
5.5H
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B
3/πH
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C
√3/πH
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D
2.5H
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Solution
The correct option is C√3/πH R=VDCIDC=1001=100Ω V2ACI2AC=R2+X2L⇒10020.52=1002+X2L⇒XL=√30000=100√3Ω XL=L2πf⇒100√3=L2π50⇒L=√3πH