The correct option is D 5
When 12 divided by a positive integer n, the remainder is (n−3).
Thus, 12=nk+(n−3), where is a k positive integer
⇒12=nk+n−3
⇒15=n(k+1)
The divisors of 15 are 1,3,5,15.
Thus, the possible values of (n,k+1) are (1,15),(15,1),(3,5),(5,3).
Now, (1,15),(15,1),(3,5) does not satisfy our initial equation 12=nk+(n−3).
Therefore n=5 is the possible value.