Question

When ${}_{15}^{30}P$ emits a _____, the daughter nuclide formed is ${}_{14}^{30}Si$.

• A. antineutrino
  
• B. positron
• C. $\alpha -particle$
• D. $\gamma -ray$

Answer 1

The correct option is B positron

When ${}_{15}^{30}P$ emits a positron, the daughter nuclide formed as ${}_{14}^{30}Si$.
${}_{15}^{30}P{\to }_{14}^{30}Si{+}_{+1}^0\beta$ The mass number remains same i.e, 30 and the atomic number decreases by 1, i.e, decreases from 15 to 14.