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Molality

when 2.94 mol...

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when 2.94 moles of Iodine and 8.1 mole of hydrogen are heated at a constant volume at 722 K until the equilbrium is achieved, 5.64 moles of HI are formed find the equilbrium constant

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Q. For the following Reaction,

H_{2 (g)} + I_{2 (g)} ⇌ 2 H I_{(g)}

25 ml

H_{2}

20 ml

I_{2}

are present in a container and at equlibrium

30 ml

H I

is formed then calculate the equlibrium constant:

Q. 4.5 moles each of hydrogen and iodine are heated in a sealed 10-liter vessel. At equilibrium 3.0 moles of HI were found.

The equilibrium constant for

H_{2} (g)

I_{2} (g) ⇌ 2 H I (g)

4.5

moles each of hydrogen and iodine are heated in a sealed

10

litre vessel. At equilibrium,

3

moles of hydrogen iodide was found.

H_{2} (g) + I_{2} (g) \Leftrightarrow 2 H I (g)

The equilibrium constant for is:

Q. 4.5 moles of each hydrogen and iodine are heated in a sealed 10-liter vessel. At equilibrium, 3 moles of hydrogen iodide was found.

The equilibrium constant for

H_{2} (g)

I_{2} (g) ⇌ 2 H I (g)

4.5

moles each of hydrogen and iodine heated in a sealed ten-litre vessel. At equilibrium,

3

H I

The equilibrium constant for

H_{2} (g)

I_{2} (g) ⇌ 2 H I (g)

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