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Byju's Answer
Standard XII
Chemistry
Molality
when 2.94 mol...
Question
when 2.94 moles of Iodine and 8.1 mole of hydrogen are heated at a constant volume at 722 K until the equilbrium is achieved, 5.64 moles of HI are formed find the equilbrium constant
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Q.
For the following Reaction,
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
,
If initially
25
ml
of
H
2
and
20
ml
of
I
2
are present in a container and at equlibrium
30
ml
of
H
I
is formed then calculate the equlibrium constant:
Q.
4.5 moles each of hydrogen and iodine are heated in a sealed 10-liter vessel. At equilibrium 3.0 moles of HI were found.
The equilibrium constant for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is:
Q.
4.5
moles each of hydrogen and iodine are heated in a sealed
10
litre vessel. At equilibrium,
3
moles of hydrogen iodide was found.
H
2
(
g
)
+
I
2
(
g
)
⇔
2
H
I
(
g
)
The equilibrium constant for is:
Q.
4.5 moles of each hydrogen and iodine are heated in a sealed 10-liter vessel. At equilibrium, 3 moles of hydrogen iodide was found.
The equilibrium constant for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is;
Q.
4.5
moles each of hydrogen and iodine heated in a sealed ten-litre vessel. At equilibrium,
3
moles of
H
I
were found.
The equilibrium constant for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is:
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