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Question
When 2-Bromo-3-methylbutane is treated with sodium ethoxide in ethanol, what will be the major product?
When 2-Bromo-3-methylbutane is treated with sodium ethoxide in ethanol, what will be the major product?
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Solution
The correct option is B 2-methyl but-2-ene
When 2-Bromo-3-methylbutane is treated with sodium ethoxide in ethanol, two alkenes are possible. The reaction mechanism follows Saytzeff's rule, hence more substituted alkene, i.e, 2−methyl−2−butene is formed as major product.
CH3−βC|CH3H−Br|CαH−CH3CH3CH2ONa−−−−−−−−→CH3CH2OHCH3−C|CH3=CH−CH32−methylbut−2−ene(major product)+CH3−C|HCH3−CH=CH23−methylbut−1−ene(minor product)
Option A is correct.
When 2-Bromo-3-methylbutane is treated with sodium ethoxide in ethanol, two alkenes are possible. The reaction mechanism follows Saytzeff's rule, hence more substituted alkene, i.e, 2−methyl−2−butene is formed as major product.
CH3−βC|CH3H−Br|CαH−CH3CH3CH2ONa−−−−−−−−→CH3CH2OHCH3−C|CH3=CH−CH32−methylbut−2−ene(major product)+CH3−C|HCH3−CH=CH23−methylbut−1−ene(minor product)
Option A is correct.
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